http://nhmath.lonestar.edu/Faculty/HortonP/Math%201332/Math%201332%20Lecture%2024%20review.pdf WebNov 20, 2013 · Suppose a simple graph G has 8 vertices. What is the maximum number of edges that the graph G can have? The formula for this I believe is . n(n-1) / 2. where n = number of vertices. 8(8-1) / 2 = 28. Therefore a simple graph with 8 vertices can have a maximum of 28 edges. Is this correct?
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WebMay 23, 2024 · If you represent the bridges and islands of Konigsberg by a graph, then the graph has 4 nodes and all 4 nodes have odd degree. To make an Eulerian circuit possible then you have to add two bridges. However, to make an Eulerian path possible (where the starting node and the end node do not have to be the same) you only have to add one … WebExpert Answer (i)There are 2 bridges -HI and DE. (ii)There are 7 … View the full answer Transcribed image text: (3) All parts of this question refer to the following graph: B с D G … greenpeace block
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WebIn the graph below, vertices A and C have degree 4, since there are 4 edges leading into each vertex. B is degree 2, D is degree 3, and E is degree 1. This graph contains two vertices with odd degree (D and E) and three vertices with even degree (A, B, and C), so Euler’s theorems tell us this graph has an Euler path, but not an Euler circuit. WebApr 5, 2024 · Apr 5, 2024 In 2024, there were nearly 617,300 road bridges in California, while Texas was the state with the highest number of road bridges, with almost 55,200 road … Webb) How many odd vertices does the graph have? 0 c) How many even vertices does the graph have? 5 d) How many bridges does the graph have? 0 e) Does the graph have an Euler path? Explain using Euler’s Theorem. Yes, since the graph has no odd vertices, it has an Euler circuit and therefore an Euler path. Vertex Degree A 4 B 4 C 4 D 2 E 4 fly reel reviews